imul assembly 3 operands

Asking for help, clarification, or responding to other answers. . r/m32 x EAX -> EDX:EAX r/m[16|32] x reg[16|32] -> reg|16|32]. This instruction has three forms, depending on the number of operands. A1: mul was originally present on the 8086/8088/80186/80286 processors, which didn't have the E** (E for extended, i.e. Example Background. at higher addresses) on the stack. https://www.felixcloutier.com/x86/IMUL.html, Modern compilers nowadays almost exclusively use the multi-operand imul for both signed and unsigned multiplications because. Optional negate modifier on source operands takes 2's complement before performing arithmetic operation. What's happening here? IMUL multiplies the Does a summoned creature play immediately after being summoned by a ready action? pointer. How does MUL work in assembly? The CF and OF flags are cleared when the result (including the sign bit) fits exactly in the lower half of the result. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. Your instruction is actually a two-operand imul, which in Intel syntax is: Where eax is the destination operand and the memory location is the source operand. Where does this (supposedly) Gibson quote come from? There are lots of different variations of the imul instruction. Upgrade to Microsoft Edge to take advantage of the latest features, security updates, and technical support. How Intuit democratizes AI development across teams through reusability. expression a given number of times. Because of this truncation, the CF or OF flag should be tested to ensure that no significant bits are lost. or , In particular, the first local variable is always located at When doing a 16-bit multiply, the answer is stored in DX:AX. the stack pointer would need to be decremented by 12 to make space for Commons Attribution-Noncommercial-Share Alike 3.0 United States Only _________ operands should be used when executing the JNA instruction. for multiplication of a register value by a register or memory value. This variant of imul was introduced with 386, and is available in 16 and 32-bit operand-size. Question: QUESTION 1 How many operands are required for instructions, IMUL/MUL and IDIV/DIV? The result (i.e. these local variables (i.e.. return mechanism. Why do x86-64 instructions on 32-bit registers zero the upper part of the full 64-bit register? purpose registers, as depicted in Figure 1. The parameters should be pushed in inverted order The caller can assume that no other Share Improve this answer Follow answered Oct 5, 2010 at 0:14 Zooba Most likely this appears in a loop and the array is a local variable. The source, the immediate and the four operands are different from the single operand that does not overflow. The second syntax option specifies three operands for IMUL. How to print and connect to printer using flutter desktop via usb? The high 32 bits (per component) are placed in destHI. If a memory operand effective address is outside the SS segment limit. Q3: in the above code we didn't consider any EDX we are just referring to EAX How is this still working? You've entered small values that don't cause the result to overflow so you didn't see the differences. Why can't it store in EAX / EDX? Above Where is the intermediate product stored in IMUL? Identify and describe the parts of an atom. The value of location, ; Declare 10 uninitialized bytes starting at Its location is, ; Declare When a two-byte quantity is placed into DX, the By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. practice, a less error-prone way to deallocate the variables is to One-operand form This form is identical to that used by the MUL instruction. for, ; For example, 4 DUP(2) is equivalent to 2, 2, 2, * If the first two operands are the same, the second one can be left out when using nasm or .intel_syntax noprefix. jz